What are the solutions to the equation 6x^2+x=2 ?

The solutions to the equation 6x^2+x=2 are x= 1/2 ,x=-2/3

Find the zeros of 6x^2+x=2

The zeros of 6x^2+x=2 are x= 1/2 ,x=-2/3

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6 x^{2} + x = 2

x = \frac{1}{2}, x = - \frac{2}{3}

Decimal Notation

x = 0.5, x = - 0.66666 \dots

Solution steps

6 x^{2} + x = 2

Move

2

to the left side

6 x^{2} + x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 6 ( - 2 )}{2 \cdot 6}

1^{2} - 4 \cdot 6 (- 2) = 7

x_{1, 2} = \frac{- 1 \pm 7}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 1 + 7}{2 \cdot 6}, x_{2} = \frac{- 1 - 7}{2 \cdot 6}

x = \frac{- 1 + 7}{2 \cdot 6} : \frac{1}{2}

x = \frac{- 1 - 7}{2 \cdot 6} : - \frac{2}{3}

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - \frac{2}{3}

x^{2} - 3 x + 0 = 0

5 x^{2} + 2 x - 5 = 0

4 - x^{2} = 3 x

(x + 7)^{2} = 25

3 - 2 x - x^{2}

What are the solutions to the equation 6x^2+x=2 ?
The solutions to the equation 6x^2+x=2 are x= 1/2 ,x=-2/3
Find the zeros of 6x^2+x=2
The zeros of 6x^2+x=2 are x= 1/2 ,x=-2/3