What are the solutions to the equation x^2+1=-8 ?

The solutions to the equation x^2+1=-8 are x=3i,x=-3i

Find the zeros of x^2+1=-8

The zeros of x^2+1=-8 are x=3i,x=-3i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 1 = - 8

x = 3 i, x = - 3 i

Solution steps

x^{2} + 1 = - 8

Move

1

to the right side

x^{2} = - 9

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 9, x = - - 9

- 9 = 3 i

- - 9 = - 3 i

x = 3 i, x = - 3 i

2 x^{2} + 4 x - 10 = 0

\frac{( x + 2 ) ^{2}}{5} + \frac{( x - 2 ) ^{2}}{3} = \frac{16}{3}

x^{2} - x - 1

(x - 5)^{2} = - 25

2 x^{2} - 7 x + 5

What are the solutions to the equation x^2+1=-8 ?
The solutions to the equation x^2+1=-8 are x=3i,x=-3i
Find the zeros of x^2+1=-8
The zeros of x^2+1=-8 are x=3i,x=-3i