What are the solutions to the equation 1x^2+1x-380=0 ?

The solutions to the equation 1x^2+1x-380=0 are x=19,x=-20

Find the zeros of 1x^2+1x-380=0

The zeros of 1x^2+1x-380=0 are x=19,x=-20

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

1 x^{2} + 1 x - 380 = 0

x = 19, x = - 20

Solution steps

1 \cdot x^{2} + 1 \cdot x - 380 = 0

Refine

x^{2} + x - 380 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 380 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 380) = 39

x_{1, 2} = \frac{- 1 \pm 39}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 39}{2 \cdot 1}, x_{2} = \frac{- 1 - 39}{2 \cdot 1}

x = \frac{- 1 + 39}{2 \cdot 1} : 19

x = \frac{- 1 - 39}{2 \cdot 1} : - 20

The solutions to the quadratic equation are:

x = 19, x = - 20

(x + 1)^{2} = - 16

x^{2} - 2 x + 7 = 4 x - 10

9 x^{2} - x - 8 = 0

x^{2} - 4 x - 36 = 0

3 x^{2} + 8 = 0

What are the solutions to the equation 1x^2+1x-380=0 ?
The solutions to the equation 1x^2+1x-380=0 are x=19,x=-20
Find the zeros of 1x^2+1x-380=0
The zeros of 1x^2+1x-380=0 are x=19,x=-20