What is factor 2t^2+9t+7 ?

The solution to factor 2t^2+9t+7 is (t+1)(2t+7)

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factor 2t^2+9t+7

factor

2 t^{2} + 9 t + 7

(t + 1) (2 t + 7)

Solution steps

2 t^{2} + 9 t + 7

Break the expression into groups

= (2 t^{2} + 2 t) + (7 t + 7)

Factor out

2 t

from

2 t^{2} + 2 t : 2 t (t + 1)

Factor out

7

from

7 t + 7 : 7 (t + 1)

= 2 t (t + 1) + 7 (t + 1)

Factor out common term

t + 1

= (t + 1) (2 t + 7)

\frac{2 x + 2}{x ^{2} + 4 x + 3} \leq \frac{3 x + 3}{3 x ^{2} + 2 x - 1}

(- 64)^{\frac{1}{3}}

\frac{( - 3 c ^{- 1} ) ^{4}}{- 12 c ^{7}}

3 x + 2 \geq 0

a^{2} + 4 - 4 a - 9 b^{2}