What are the solutions to the equation (2a+x)^2=4a^2+8ab^2+4b^4 ?

The solutions to the equation (2a+x)^2=4a^2+8ab^2+4b^4 are x=2b^2,x=-4a-2b^2

Find the zeros of (2a+x)^2=4a^2+8ab^2+4b^4

The zeros of (2a+x)^2=4a^2+8ab^2+4b^4 are x=2b^2,x=-4a-2b^2

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(2 a + x)^{2} = 4 a^{2} + 8 a b^{2} + 4 b^{4}

x = 2 b^{2}, x = - 4 a - 2 b^{2}

Solution steps

(2 a + x)^{2} = 4 a^{2} + 8 a b^{2} + 4 b^{4}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 a + x = 4 a^{2} + 8 a b^{2} + 4 b^{4} : x = 2 b^{2}

Solve

2 a + x = - 4 a^{2} + 8 a b^{2} + 4 b^{4} : x = - 4 a - 2 b^{2}

The solutions to the quadratic equation are:

x = 2 b^{2}, x = - 4 a - 2 b^{2}

2 x^{2} + 3 x = - 13

3 y^{2} - 8 y + 4 = 0

7 x + 4 x^{2} + 4 = 2

1^{2} + 2^{2} = x^{2}

6 x = x^{2} + 7

What are the solutions to the equation (2a+x)^2=4a^2+8ab^2+4b^4 ?
The solutions to the equation (2a+x)^2=4a^2+8ab^2+4b^4 are x=2b^2,x=-4a-2b^2
Find the zeros of (2a+x)^2=4a^2+8ab^2+4b^4
The zeros of (2a+x)^2=4a^2+8ab^2+4b^4 are x=2b^2,x=-4a-2b^2