What are the solutions to the equation (3x-4)^2-1=24 ?

The solutions to the equation (3x-4)^2-1=24 are x=3,x=-1/3

Find the zeros of (3x-4)^2-1=24

The zeros of (3x-4)^2-1=24 are x=3,x=-1/3

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(3 x - 4)^{2} - 1 = 24

x = 3, x = - \frac{1}{3}

Decimal Notation

x = 3, x = - 0.33333 \dots

Solution steps

(3 x - 4)^{2} - 1 = 24

Move

1

to the right side

(3 x - 4)^{2} = 25

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x - 4 = 25 : x = 3

Solve

3 x - 4 = - 25 : x = - \frac{1}{3}

The solutions to the quadratic equation are:

x = 3, x = - \frac{1}{3}

x, x^{2} - 2.5 x + 1.5 = 0

8 x^{2} + 32 x - 10 = 0

x^{2} - 2 x - 4 = 0

- x^{2} + 8 x + 9 = 0

x^{2} - 2 x - 3 = 0

What are the solutions to the equation (3x-4)^2-1=24 ?
The solutions to the equation (3x-4)^2-1=24 are x=3,x=-1/3
Find the zeros of (3x-4)^2-1=24
The zeros of (3x-4)^2-1=24 are x=3,x=-1/3