What are the solutions to the equation x^2-27x+65=-13x ?

The solutions to the equation x^2-27x+65=-13x are x=7+4i,x=7-4i

Find the zeros of x^2-27x+65=-13x

The zeros of x^2-27x+65=-13x are x=7+4i,x=7-4i

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x^{2} - 27 x + 65 = - 13 x

x = 7 + 4 i, x = 7 - 4 i

Solution steps

x^{2} - 27 x + 65 = - 13 x

Move

13 x

to the left side

x^{2} - 14 x + 65 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 65}{2 \cdot 1}

Simplify

(- 14)^{2} - 4 \cdot 1 \cdot 65 : 8 i

x_{1, 2} = \frac{- ( - 14 ) \pm 8 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 8 i}{2 \cdot 1}, x_{2} = \frac{- ( - 14 ) - 8 i}{2 \cdot 1}

x = \frac{- ( - 14 ) + 8 i}{2 \cdot 1} : 7 + 4 i

x = \frac{- ( - 14 ) - 8 i}{2 \cdot 1} : 7 - 4 i

The solutions to the quadratic equation are:

x = 7 + 4 i, x = 7 - 4 i

x^{2} + 14 x + 30 = 0

9 x^{2} + 7 x - 4 = 0

x^{2} - 4 x - 1

x^{2} - 4 x - 5

x^{2} - 6 x + 9 = 81

What are the solutions to the equation x^2-27x+65=-13x ?
The solutions to the equation x^2-27x+65=-13x are x=7+4i,x=7-4i
Find the zeros of x^2-27x+65=-13x
The zeros of x^2-27x+65=-13x are x=7+4i,x=7-4i