What are the solutions to the equation 3^2+b^2=6^2 ?

The solutions to the equation 3^2+b^2=6^2 are b=3sqrt(3),b=-3sqrt(3)

Find the zeros of 3^2+b^2=6^2

The zeros of 3^2+b^2=6^2 are b=3sqrt(3),b=-3sqrt(3)

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3^{2} + b^{2} = 6^{2}

b = 33, b = - 33

Decimal Notation

b = 5.19615 \dots, b = - 5.19615 \dots

Solution steps

3^{2} + b^{2} = 6^{2}

Move

3^{2}

to the right side

b^{2} = 27

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 27, b = - 27

27 = 33

- 27 = - 33

b = 33, b = - 33

1 0^{2} + x^{2} = 2 0^{2}

(x + 1)^{2} + (x - 8)^{2} = 45

x^{2} + 6 x + 5 = 0

x^{2} + 15 x + 54

(x - 4)^{2} = 2 x

What are the solutions to the equation 3^2+b^2=6^2 ?
The solutions to the equation 3^2+b^2=6^2 are b=3sqrt(3),b=-3sqrt(3)
Find the zeros of 3^2+b^2=6^2
The zeros of 3^2+b^2=6^2 are b=3sqrt(3),b=-3sqrt(3)