What are the solutions to the equation (x+1)^2+(x-8)^2=45 ?

The solutions to the equation (x+1)^2+(x-8)^2=45 are x=5,x=2

Find the zeros of (x+1)^2+(x-8)^2=45

The zeros of (x+1)^2+(x-8)^2=45 are x=5,x=2

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(x + 1)^{2} + (x - 8)^{2} = 45

x = 5, x = 2

Solution steps

(x + 1)^{2} + (x - 8)^{2} = 45

Expand

(x + 1)^{2} + (x - 8)^{2} : 2 x^{2} - 14 x + 65

2 x^{2} - 14 x + 65 = 45

Move

45

to the left side

2 x^{2} - 14 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 2 \cdot 20}{2 \cdot 2}

(- 14)^{2} - 4 \cdot 2 \cdot 20 = 6

x_{1, 2} = \frac{- ( - 14 ) \pm 6}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 6}{2 \cdot 2}, x_{2} = \frac{- ( - 14 ) - 6}{2 \cdot 2}

x = \frac{- ( - 14 ) + 6}{2 \cdot 2} : 5

x = \frac{- ( - 14 ) - 6}{2 \cdot 2} : 2

The solutions to the quadratic equation are:

x = 5, x = 2

x^{2} + 6 x + 5 = 0

x^{2} + 15 x + 54

(x - 4)^{2} = 2 x

(2 - x)^{2} = 2

9 x^{2} - 48 x + 68 = 0

What are the solutions to the equation (x+1)^2+(x-8)^2=45 ?
The solutions to the equation (x+1)^2+(x-8)^2=45 are x=5,x=2
Find the zeros of (x+1)^2+(x-8)^2=45
The zeros of (x+1)^2+(x-8)^2=45 are x=5,x=2