What are the solutions to the equation (2-x)^2=2 ?

The solutions to the equation (2-x)^2=2 are x=2-sqrt(2),x=2+sqrt(2)

Find the zeros of (2-x)^2=2

The zeros of (2-x)^2=2 are x=2-sqrt(2),x=2+sqrt(2)

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(2 - x)^{2} = 2

x = 2 - 2, x = 2 + 2

Decimal Notation

x = 0.58578 \dots, x = 3.41421 \dots

Solution steps

(2 - x)^{2} = 2

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 - x = 2 : x = 2 - 2

Solve

2 - x = - 2 : x = 2 + 2

The solutions to the quadratic equation are:

x = 2 - 2, x = 2 + 2

9 x^{2} - 48 x + 68 = 0

x^{2} - 44 x = - 3.84

x^{2} + 0.1 x - 4.62 = 0

- 8 x + 4 x^{2} = - 4 - 2 x

r^{2} - 2 r - 15 = 0

What are the solutions to the equation (2-x)^2=2 ?
The solutions to the equation (2-x)^2=2 are x=2-sqrt(2),x=2+sqrt(2)
Find the zeros of (2-x)^2=2
The zeros of (2-x)^2=2 are x=2-sqrt(2),x=2+sqrt(2)