What are the solutions to the equation 4x^2+3x-27=0 ?

The solutions to the equation 4x^2+3x-27=0 are x= 9/4 ,x=-3

Find the zeros of 4x^2+3x-27=0

The zeros of 4x^2+3x-27=0 are x= 9/4 ,x=-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} + 3 x - 27 = 0

x = \frac{9}{4}, x = - 3

Decimal Notation

x = 2.25, x = - 3

Solution steps

4 x^{2} + 3 x - 27 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 4 ( - 27 )}{2 \cdot 4}

3^{2} - 4 \cdot 4 (- 27) = 21

x_{1, 2} = \frac{- 3 \pm 21}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 3 + 21}{2 \cdot 4}, x_{2} = \frac{- 3 - 21}{2 \cdot 4}

x = \frac{- 3 + 21}{2 \cdot 4} : \frac{9}{4}

x = \frac{- 3 - 21}{2 \cdot 4} : - 3

The solutions to the quadratic equation are:

x = \frac{9}{4}, x = - 3

4 x^{2} + 4 x - 2 = 0

n^{2} - 2 n - 24 = 0

6 x^{2} = 13 x + 5

x^{2} - 5 x - 1

x^{2} - 5 x + 8

What are the solutions to the equation 4x^2+3x-27=0 ?
The solutions to the equation 4x^2+3x-27=0 are x= 9/4 ,x=-3
Find the zeros of 4x^2+3x-27=0
The zeros of 4x^2+3x-27=0 are x= 9/4 ,x=-3