What are the solutions to the equation n^2-2n-24=0 ?

The solutions to the equation n^2-2n-24=0 are n=6,n=-4

Find the zeros of n^2-2n-24=0

The zeros of n^2-2n-24=0 are n=6,n=-4

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n^{2} - 2 n - 24 = 0

n = 6, n = - 4

Solution steps

n^{2} - 2 n - 24 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 24 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 24) = 10

n_{1, 2} = \frac{- ( - 2 ) \pm 10}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- ( - 2 ) + 10}{2 \cdot 1}, n_{2} = \frac{- ( - 2 ) - 10}{2 \cdot 1}

n = \frac{- ( - 2 ) + 10}{2 \cdot 1} : 6

n = \frac{- ( - 2 ) - 10}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

n = 6, n = - 4

6 x^{2} = 13 x + 5

x^{2} - 5 x - 1

x^{2} - 5 x + 8

- 3 x^{2} - 3 = 0

- 0.5 x^{2} + 40 x - 300 = 50

What are the solutions to the equation n^2-2n-24=0 ?
The solutions to the equation n^2-2n-24=0 are n=6,n=-4
Find the zeros of n^2-2n-24=0
The zeros of n^2-2n-24=0 are n=6,n=-4