What are the solutions to the equation x^2+12x+1=0 ?

The solutions to the equation x^2+12x+1=0 are x=-6+sqrt(35),x=-6-sqrt(35)

Find the zeros of x^2+12x+1=0

The zeros of x^2+12x+1=0 are x=-6+sqrt(35),x=-6-sqrt(35)

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x^{2} + 12 x + 1 = 0

x = - 6 + 35, x = - 6 - 35

Decimal Notation

x = - 0.08392 \dots, x = - 11.91607 \dots

Solution steps

x^{2} + 12 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot 1 = 235

x_{1, 2} = \frac{- 12 \pm 2 35}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 12 + 2 35}{2 \cdot 1}, x_{2} = \frac{- 12 - 2 35}{2 \cdot 1}

x = \frac{- 12 + 2 35}{2 \cdot 1} : - 6 + 35

x = \frac{- 12 - 2 35}{2 \cdot 1} : - 6 - 35

The solutions to the quadratic equation are:

x = - 6 + 35, x = - 6 - 35

x^{2} - 20 x = 96

x, (3 x y + 7)^{2} = 6 y

x^{2} + \frac{4}{3} x = 0

3 m^{2} - 5 m = 7

x, x^{2} + 4 x + 16 y^{2} - 128 y + 292 = 0

What are the solutions to the equation x^2+12x+1=0 ?
The solutions to the equation x^2+12x+1=0 are x=-6+sqrt(35),x=-6-sqrt(35)
Find the zeros of x^2+12x+1=0
The zeros of x^2+12x+1=0 are x=-6+sqrt(35),x=-6-sqrt(35)