What are the solutions to the equation 4x=x^2-12 ?

The solutions to the equation 4x=x^2-12 are x=6,x=-2

Find the zeros of 4x=x^2-12

The zeros of 4x=x^2-12 are x=6,x=-2

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4 x = x^{2} - 12

x = 6, x = - 2

Solution steps

4 x = x^{2} - 12

Switch sides

x^{2} - 12 = 4 x

Move

4 x

to the left side

x^{2} - 12 - 4 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 4 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 12) = 8

x_{1, 2} = \frac{- ( - 4 ) \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 8}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 8}{2 \cdot 1}

x = \frac{- ( - 4 ) + 8}{2 \cdot 1} : 6

x = \frac{- ( - 4 ) - 8}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 6, x = - 2

4 x^{2} + x - 7 = 0

x = \frac{9 ( - 3 ) - 2 ( - 2 )}{15 ( - 3 ) - 3 ( - 2 )}

8 - \frac{x}{3} \leq 7

(- 6)^{- 2}

x - 1 + 4 x = 3 x - 11

What are the solutions to the equation 4x=x^2-12 ?
The solutions to the equation 4x=x^2-12 are x=6,x=-2
Find the zeros of 4x=x^2-12
The zeros of 4x=x^2-12 are x=6,x=-2