What are the solutions to the equation x^2-4.9x+2.2=0 ?

The solutions to the equation x^2-4.9x+2.2=0 are x= 22/5 ,x= 1/2

Find the zeros of x^2-4.9x+2.2=0

The zeros of x^2-4.9x+2.2=0 are x= 22/5 ,x= 1/2

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x^{2} - 4.9 x + 2.2 = 0

x = \frac{22}{5}, x = \frac{1}{2}

Decimal Notation

x = 4.4, x = 0.5

Solution steps

x^{2} - 4.9 x + 2.2 = 0

Multiply both sides by

10

10 x^{2} - 49 x + 22 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 49 ) \pm ( - 49 ) ^{2} - 4 \cdot 10 \cdot 22}{2 \cdot 10}

(- 49)^{2} - 4 \cdot 10 \cdot 22 = 39

x_{1, 2} = \frac{- ( - 49 ) \pm 39}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- ( - 49 ) + 39}{2 \cdot 10}, x_{2} = \frac{- ( - 49 ) - 39}{2 \cdot 10}

x = \frac{- ( - 49 ) + 39}{2 \cdot 10} : \frac{22}{5}

x = \frac{- ( - 49 ) - 39}{2 \cdot 10} : \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{22}{5}, x = \frac{1}{2}

6 x^{2} + 3 = 0

y^{2} = - 6

x, x^{2} = y

x = 4 x - x^{2}

x^{2} + 10 x + 25 = 121

What are the solutions to the equation x^2-4.9x+2.2=0 ?
The solutions to the equation x^2-4.9x+2.2=0 are x= 22/5 ,x= 1/2
Find the zeros of x^2-4.9x+2.2=0
The zeros of x^2-4.9x+2.2=0 are x= 22/5 ,x= 1/2