What is the answer to 2x+(1/4)/3-x/6 =(1/3)^2 ?

The answer to 2x+(1/4)/3-x/6 =(1/3)^2 is x= 1/66

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2x+(1/4)/3-x/6 =(1/3)^2

2 x + \frac{\frac{1}{4}}{3} - \frac{x}{6} = (\frac{1}{3})^{2}

x = \frac{1}{66}

Solution steps

2 x + \frac{\frac{1}{4}}{3} - \frac{x}{6} = (\frac{1}{3})^{2}

Simplify

2 x + \frac{\frac{1}{4}}{3} - \frac{x}{6} : 2 x + \frac{1}{12} - \frac{x}{6}

Simplify

(\frac{1}{3})^{2} : \frac{1}{9}

2 x + \frac{1}{12} - \frac{x}{6} = \frac{1}{9}

Move

\frac{1}{12}

to the right side

2 x - \frac{x}{6} = \frac{1}{36}

Multiply both sides by

6

11 x = \frac{1}{6}

Divide both sides by

11

x = \frac{1}{66}

4 x^{2} + 6 x + 9 = 0

14 x^{2} + 33 x + 18

3 (x + 4) - 2 (2 + 2 x) = 3 (x - 6 x + 12 + 2)

3 (h - 4) + 2 h - 5 + 2 (h + 1) = 9

2 x^{2} - 11 x + 12 = 0

What is the answer to 2x+(1/4)/3-x/6 =(1/3)^2 ?
The answer to 2x+(1/4)/3-x/6 =(1/3)^2 is x= 1/66
Solve for x: 2x+(1/4)/3-x/6 =(1/3)^2
The solution is x= 1/66