What is the answer to 3(x+4)-2(2+2x)=3(x-6x+12+2) ?

The answer to 3(x+4)-2(2+2x)=3(x-6x+12+2) is x= 17/7

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3(x+4)-2(2+2x)=3(x-6x+12+2)

3 (x + 4) - 2 (2 + 2 x) = 3 (x - 6 x + 12 + 2)

x = \frac{17}{7}

Solution steps

3 (x + 4) - 2 (2 + 2 x) = 3 (x - 6 x + 12 + 2)

Expand

3 (x + 4) - 2 (2 + 2 x) : - x + 8

Expand

3 (x - 6 x + 12 + 2) : - 15 x + 42

- x + 8 = - 15 x + 42

Move

8

to the right side

- x = - 15 x + 34

Move

15 x

to the left side

14 x = 34

Divide both sides by

14

x = \frac{17}{7}

3 (h - 4) + 2 h - 5 + 2 (h + 1) = 9

2 x^{2} - 11 x + 12 = 0

2 x^{2} + 7 x + 1 = 0

\frac{1}{2} x - 5 = \frac{3}{10} x

(x + 1) (x - 3) = 0

What is the answer to 3(x+4)-2(2+2x)=3(x-6x+12+2) ?
The answer to 3(x+4)-2(2+2x)=3(x-6x+12+2) is x= 17/7
Solve for x: 3(x+4)-2(2+2x)=3(x-6x+12+2)
The solution is x= 17/7