What are the solutions to the equation (x+1)(x-3)=0 ?

The solutions to the equation (x+1)(x-3)=0 are x=-1,x=3

Find the zeros of (x+1)(x-3)=0

The zeros of (x+1)(x-3)=0 are x=-1,x=3

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(x + 1) (x - 3) = 0

x = - 1, x = 3

Solution steps

(x + 1) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x - 3 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x - 3 = 0 : x = 3

The solutions to the quadratic equation are:

x = - 1, x = 3

1 2^{2} + x^{2} = 1 3^{2}

4 x^{2} + 9 x - 10 = 0

3 (x + 3) = 7 (x - 2)

- 3 \cdot \frac{3}{2}

∣ x + 7 ∣ > 2

What are the solutions to the equation (x+1)(x-3)=0 ?
The solutions to the equation (x+1)(x-3)=0 are x=-1,x=3
Find the zeros of (x+1)(x-3)=0
The zeros of (x+1)(x-3)=0 are x=-1,x=3