What are the solutions to the equation x^2+4=1 ?

The solutions to the equation x^2+4=1 are x=sqrt(3)i,x=-sqrt(3)i

Find the zeros of x^2+4=1

The zeros of x^2+4=1 are x=sqrt(3)i,x=-sqrt(3)i

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x^{2} + 4 = 1

x = 3 i, x = - 3 i

Solution steps

x^{2} + 4 = 1

Move

4

to the right side

x^{2} = - 3

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 3, x = - - 3

- 3 = 3 i

- - 3 = - 3 i

x = 3 i, x = - 3 i

x, x^{2} - 3 x + 1 = 0

x^{2} - 0.01 = 0.03

104 - 84 x + 12 x^{2} = 0

2 x^{2} - 8 x + 5

- 23 = x^{2} + 8 x

What are the solutions to the equation x^2+4=1 ?
The solutions to the equation x^2+4=1 are x=sqrt(3)i,x=-sqrt(3)i
Find the zeros of x^2+4=1
The zeros of x^2+4=1 are x=sqrt(3)i,x=-sqrt(3)i