What are the solutions to the equation x^2+4=2x ?

The solutions to the equation x^2+4=2x are x=1+sqrt(3)i,x=1-sqrt(3)i

Find the zeros of x^2+4=2x

The zeros of x^2+4=2x are x=1+sqrt(3)i,x=1-sqrt(3)i

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x^{2} + 4 = 2 x

x = 1 + 3 i, x = 1 - 3 i

Solution steps

x^{2} + 4 = 2 x

Move

2 x

to the left side

x^{2} + 4 - 2 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 2 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 4 : 23 i

x_{1, 2} = \frac{- ( - 2 ) \pm 2 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 3 i}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 3 i}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 3 i}{2 \cdot 1} : 1 + 3 i

x = \frac{- ( - 2 ) - 2 3 i}{2 \cdot 1} : 1 - 3 i

The solutions to the quadratic equation are:

x = 1 + 3 i, x = 1 - 3 i

6 x^{2} + x + 2 = 0

x^{2} = 6 x + 11

9 x^{2} - 6 x = - 9

- 2 x^{2} + 18 x = 0

- 17 x^{2} + 64 x = 48

What are the solutions to the equation x^2+4=2x ?
The solutions to the equation x^2+4=2x are x=1+sqrt(3)i,x=1-sqrt(3)i
Find the zeros of x^2+4=2x
The zeros of x^2+4=2x are x=1+sqrt(3)i,x=1-sqrt(3)i