What are the solutions to the equation x^2+14x+39=0 ?

The solutions to the equation x^2+14x+39=0 are x=-7+sqrt(10),x=-7-sqrt(10)

Find the zeros of x^2+14x+39=0

The zeros of x^2+14x+39=0 are x=-7+sqrt(10),x=-7-sqrt(10)

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x^{2} + 14 x + 39 = 0

x = - 7 + 10, x = - 7 - 10

Decimal Notation

x = - 3.83772 \dots, x = - 10.16227 \dots

Solution steps

x^{2} + 14 x + 39 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot 39}{2 \cdot 1}

1 4^{2} - 4 \cdot 1 \cdot 39 = 210

x_{1, 2} = \frac{- 14 \pm 2 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 14 + 2 10}{2 \cdot 1}, x_{2} = \frac{- 14 - 2 10}{2 \cdot 1}

x = \frac{- 14 + 2 10}{2 \cdot 1} : - 7 + 10

x = \frac{- 14 - 2 10}{2 \cdot 1} : - 7 - 10

The solutions to the quadratic equation are:

x = - 7 + 10, x = - 7 - 10

x, 9 y^{2} - 18 y - 16 x^{2} + 32 x - 7 = 0

(x - 2) (x - 1) = 0

- x^{2} = - 1

x, z = 3 x^{2}

x, 3 x^{2} z - x^{2} y^{2} + 2 z^{3} + 3 yz - 5 = 0

What are the solutions to the equation x^2+14x+39=0 ?
The solutions to the equation x^2+14x+39=0 are x=-7+sqrt(10),x=-7-sqrt(10)
Find the zeros of x^2+14x+39=0
The zeros of x^2+14x+39=0 are x=-7+sqrt(10),x=-7-sqrt(10)