What are the solutions to the equation 3x(x+1)+56=5x+86-2x ?

The solutions to the equation 3x(x+1)+56=5x+86-2x are x=sqrt(10),x=-sqrt(10)

Find the zeros of 3x(x+1)+56=5x+86-2x

The zeros of 3x(x+1)+56=5x+86-2x are x=sqrt(10),x=-sqrt(10)

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3 x (x + 1) + 56 = 5 x + 86 - 2 x

x = 10, x = - 10

Decimal Notation

x = 3.16227 \dots, x = - 3.16227 \dots

Solution steps

3 x (x + 1) + 56 = 5 x + 86 - 2 x

Expand

3 x (x + 1) + 56 : 3 x^{2} + 3 x + 56

3 x^{2} + 3 x + 56 = 3 x + 86

Move

56

to the right side

3 x^{2} + 3 x = 3 x + 30

Move

3 x

to the left side

3 x^{2} = 30

Divide both sides by

3

x^{2} = 10

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 10, x = - 10

3 x^{2} = 81 - x^{2}

x^{2} - 7 x + 12 = 0

5^{2} + 8^{2} = x^{2}

x, f = 5 x^{2} + 4 x + 4 mn - 2

x, x^{2} + y^{2} + 2 x - 8 y + 25 = 0

What are the solutions to the equation 3x(x+1)+56=5x+86-2x ?
The solutions to the equation 3x(x+1)+56=5x+86-2x are x=sqrt(10),x=-sqrt(10)
Find the zeros of 3x(x+1)+56=5x+86-2x
The zeros of 3x(x+1)+56=5x+86-2x are x=sqrt(10),x=-sqrt(10)