What is the answer to (x-3)(x-3)=x^2-3x-3x+(-3)(-3) ?

The answer to (x-3)(x-3)=x^2-3x-3x+(-3)(-3) is True for all x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x-3)(x-3)=x^2-3x-3x+(-3)(-3)

(x - 3) (x - 3) = x^{2} - 3 x - 3 x + (- 3) (- 3)

True for all x

Solution steps

(x - 3) (x - 3) = x^{2} - 3 x - 3 x + (- 3) (- 3)

Simplify

(x - 3) (x - 3) : (x - 3)^{2}

Simplify

x^{2} - 3 x - 3 x + (- 3) (- 3) : x^{2} - 6 x + 9

(x - 3)^{2} = x^{2} - 6 x + 9

Expand

(x - 3)^{2} : x^{2} - 6 x + 9

x^{2} - 6 x + 9 = x^{2} - 6 x + 9

Move

9

to the right side

x^{2} - 6 x = x^{2} - 6 x

Subtract

x^{2} - 6 x

from both sides

x^{2} - 6 x - (x^{2} - 6 x) = x^{2} - 6 x - (x^{2} - 6 x)

Simplify

0 = 0

Both sides are equal

True for all x

\frac{1.09 \cdot 1 0 ^{12}}{2.18 \cdot 1 0 ^{10}}

x^{2} + 15 x - 54 = 0

4 2^{2}

lo g_{0.1} (17)

4 + \frac{x}{1 - x} \geq \frac{2}{1 - x}

What is the answer to (x-3)(x-3)=x^2-3x-3x+(-3)(-3) ?
The answer to (x-3)(x-3)=x^2-3x-3x+(-3)(-3) is True for all x
Solve for x: (x-3)(x-3)=x^2-3x-3x+(-3)(-3)
The solution is True for all x