What are the solutions to the equation -x^2+4.6x-5.29=0 ?

The solutions to the equation -x^2+4.6x-5.29=0 are x= 23/10

Find the zeros of -x^2+4.6x-5.29=0

The zeros of -x^2+4.6x-5.29=0 are x= 23/10

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- x^{2} + 4.6 x - 5.29 = 0

x = \frac{23}{10}

Decimal Notation

x = 2.3

Solution steps

- x^{2} + 4.6 x - 5.29 = 0

Multiply both sides by

100

- 100 x^{2} + 460 x - 529 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 460 \pm 46 0 ^{2} - 4 ( - 100 ) ( - 529 )}{2 ( - 100 )}

46 0^{2} - 4 (- 100) (- 529) = 0

x_{1, 2} = \frac{- 460 \pm 0}{2 ( - 100 )}

x = \frac{- 460}{2 ( - 100 )}

\frac{- 460}{2 ( - 100 )} = \frac{23}{10}

x = \frac{23}{10}

The solution to the quadratic equation is:

x = \frac{23}{10}

X^{2} - 6 X + 1 = 0

x, 6 x^{2} y + 5 y^{3} + 3 x^{2} = 12 - x^{2} y^{2}

x^{2} + 9 x = 43.75

3 x^{2} - 24 x + 40 = 28

s^{2} - s - 2 = 0

What are the solutions to the equation -x^2+4.6x-5.29=0 ?
The solutions to the equation -x^2+4.6x-5.29=0 are x= 23/10
Find the zeros of -x^2+4.6x-5.29=0
The zeros of -x^2+4.6x-5.29=0 are x= 23/10