What are the solutions to the equation -2(x+1)^2=72 ?

The solutions to the equation -2(x+1)^2=72 are x=6i-1,x=-6i-1

Find the zeros of -2(x+1)^2=72

The zeros of -2(x+1)^2=72 are x=6i-1,x=-6i-1

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- 2 (x + 1)^{2} = 72

x = 6 i - 1, x = - 6 i - 1

Solution steps

- 2 (x + 1)^{2} = 72

Divide both sides by

- 2

(x + 1)^{2} = - 36

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 1 = - 36 : x = 6 i - 1

Solve

x + 1 = - - 36 : x = - 6 i - 1

The solutions to the quadratic equation are:

x = 6 i - 1, x = - 6 i - 1

3 x^{2} - 6 x = - 2

3 r^{2} + 8 r - 3 = 0

x^{2} + 2 x - 5 = 0

x^{2} - 18 x + 86 = 0

3 x^{2} + 17 x - 28 = 0

What are the solutions to the equation -2(x+1)^2=72 ?
The solutions to the equation -2(x+1)^2=72 are x=6i-1,x=-6i-1
Find the zeros of -2(x+1)^2=72
The zeros of -2(x+1)^2=72 are x=6i-1,x=-6i-1