What are the solutions to the equation z^2-7z-12=-5z ?

The solutions to the equation z^2-7z-12=-5z are z=1+sqrt(13),z=1-sqrt(13)

Find the zeros of z^2-7z-12=-5z

The zeros of z^2-7z-12=-5z are z=1+sqrt(13),z=1-sqrt(13)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

z^{2} - 7 z - 12 = - 5 z

z = 1 + 13, z = 1 - 13

Decimal Notation

z = 4.60555 \dots, z = - 2.60555 \dots

Solution steps

z^{2} - 7 z - 12 = - 5 z

Move

5 z

to the left side

z^{2} - 2 z - 12 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 12) = 213

z_{1, 2} = \frac{- ( - 2 ) \pm 2 13}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- ( - 2 ) + 2 13}{2 \cdot 1}, z_{2} = \frac{- ( - 2 ) - 2 13}{2 \cdot 1}

z = \frac{- ( - 2 ) + 2 13}{2 \cdot 1} : 1 + 13

z = \frac{- ( - 2 ) - 2 13}{2 \cdot 1} : 1 - 13

The solutions to the quadratic equation are:

z = 1 + 13, z = 1 - 13

5 x^{2} - 20 x + 18

a^{2} - 7 a + 6 = 0

6 + (p + 8)^{2} = 31

x^{2} = 20 x

4 x^{2} + 8 x + 6 = 0

What are the solutions to the equation z^2-7z-12=-5z ?
The solutions to the equation z^2-7z-12=-5z are z=1+sqrt(13),z=1-sqrt(13)
Find the zeros of z^2-7z-12=-5z
The zeros of z^2-7z-12=-5z are z=1+sqrt(13),z=1-sqrt(13)