What are the solutions to the equation 3x^2+23x=-14 ?

The solutions to the equation 3x^2+23x=-14 are x=-2/3 ,x=-7

Find the zeros of 3x^2+23x=-14

The zeros of 3x^2+23x=-14 are x=-2/3 ,x=-7

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3 x^{2} + 23 x = - 14

x = - \frac{2}{3}, x = - 7

Decimal Notation

x = - 0.66666 \dots, x = - 7

Solution steps

3 x^{2} + 23 x = - 14

Move

14

to the left side

3 x^{2} + 23 x + 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 23 \pm 2 3 ^{2} - 4 \cdot 3 \cdot 14}{2 \cdot 3}

2 3^{2} - 4 \cdot 3 \cdot 14 = 19

x_{1, 2} = \frac{- 23 \pm 19}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 23 + 19}{2 \cdot 3}, x_{2} = \frac{- 23 - 19}{2 \cdot 3}

x = \frac{- 23 + 19}{2 \cdot 3} : - \frac{2}{3}

x = \frac{- 23 - 19}{2 \cdot 3} : - 7

The solutions to the quadratic equation are:

x = - \frac{2}{3}, x = - 7

(2 x + 1)^{2} + 3 = 21

x^{2} - 16 = 5 x^{2}

x^{2} + 3 x = - x - 2

10 x^{2} + 20 x + 9 = 0

- 3 x^{2} + 14 x - 15 = 0

What are the solutions to the equation 3x^2+23x=-14 ?
The solutions to the equation 3x^2+23x=-14 are x=-2/3 ,x=-7
Find the zeros of 3x^2+23x=-14
The zeros of 3x^2+23x=-14 are x=-2/3 ,x=-7