What are the solutions to the equation 10x^2+20x+9=0 ?

The solutions to the equation 10x^2+20x+9=0 are x=(-10+sqrt(10))/(10),x=-(sqrt(10)+1)/(sqrt(10))

Find the zeros of 10x^2+20x+9=0

The zeros of 10x^2+20x+9=0 are x=(-10+sqrt(10))/(10),x=-(sqrt(10)+1)/(sqrt(10))

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10 x^{2} + 20 x + 9 = 0

x = \frac{- 10 + 10}{10}, x = - \frac{10 + 1}{10}

Decimal Notation

x = - 0.68377 \dots, x = - 1.31622 \dots

Solution steps

10 x^{2} + 20 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 10 \cdot 9}{2 \cdot 10}

2 0^{2} - 4 \cdot 10 \cdot 9 = 210

x_{1, 2} = \frac{- 20 \pm 2 10}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- 20 + 2 10}{2 \cdot 10}, x_{2} = \frac{- 20 - 2 10}{2 \cdot 10}

x = \frac{- 20 + 2 10}{2 \cdot 10} : \frac{- 10 + 10}{10}

x = \frac{- 20 - 2 10}{2 \cdot 10} : - \frac{10 + 1}{10}

The solutions to the quadratic equation are:

x = \frac{- 10 + 10}{10}, x = - \frac{10 + 1}{10}

- 3 x^{2} + 14 x - 15 = 0

x^{2} - 4 x - 31 = - 2 x + 25

v, F = \frac{m v ^{2}}{r}

(k - 3)^{2} = 121

x^{2} + 11 = 12 x

What are the solutions to the equation 10x^2+20x+9=0 ?
The solutions to the equation 10x^2+20x+9=0 are x=(-10+sqrt(10))/(10),x=-(sqrt(10)+1)/(sqrt(10))
Find the zeros of 10x^2+20x+9=0
The zeros of 10x^2+20x+9=0 are x=(-10+sqrt(10))/(10),x=-(sqrt(10)+1)/(sqrt(10))