What are the solutions to the equation r^2-3r=10 ?

The solutions to the equation r^2-3r=10 are r=5,r=-2

Find the zeros of r^2-3r=10

The zeros of r^2-3r=10 are r=5,r=-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

r^{2} - 3 r = 10

r = 5, r = - 2

Solution steps

r^{2} - 3 r = 10

Move

10

to the left side

r^{2} - 3 r - 10 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 10) = 7

r_{1, 2} = \frac{- ( - 3 ) \pm 7}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- ( - 3 ) + 7}{2 \cdot 1}, r_{2} = \frac{- ( - 3 ) - 7}{2 \cdot 1}

r = \frac{- ( - 3 ) + 7}{2 \cdot 1} : 5

r = \frac{- ( - 3 ) - 7}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

r = 5, r = - 2

w^{2} + 13 w + 42 = 0

m, L m^{2} + R m + \frac{1}{C} = 0

4 0^{2} + x^{2} = 4 1^{2}

3 m^{2} + 5 m = 6

2 m^{2} - 3 m - 4 = 0

What are the solutions to the equation r^2-3r=10 ?
The solutions to the equation r^2-3r=10 are r=5,r=-2
Find the zeros of r^2-3r=10
The zeros of r^2-3r=10 are r=5,r=-2