What are the solutions to the equation (3.2*10^{-5})(2-x)^2=(6.9*10^{-6})x^2 ?

The solutions to the equation (3.2*10^{-5})(2-x)^2=(6.9*10^{-6})x^2 are

Find the zeros of (3.2*10^{-5})(2-x)^2=(6.9*10^{-6})x^2

The zeros of (3.2*10^{-5})(2-x)^2=(6.9*10^{-6})x^2 are

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(3.2 \cdot 1 0^{- 5}) (2 - x)^{2} = (6.9 \cdot 1 0^{- 6}) x^{2}

x = \frac{50 ( 100000 \frac{163.84}{1 0 ^{10}} - \frac{200.8}{15625000000} + 12.8 )}{251}, x = \frac{50 ( - 100000 \frac{163.84}{1 0 ^{10}} - \frac{200.8}{15625000000} + 12.8 )}{251}

Solution steps

(3.2 \cdot 1 0^{- 5}) (2 - x)^{2} = (6.9 \cdot 1 0^{- 6}) x^{2}

Move

(6.9 \cdot 1 0^{- 6}) x^{2}

to the left side

2^{2} \cdot \frac{1}{2 \cdot 5 ^{6}} - \frac{12.8 x}{1 0 ^{5}} + \frac{25.1 x ^{2}}{1000000} = 0

Write in the standard form

a x^{2} + b x + c = 0

\frac{25.1 x ^{2}}{1000000} - \frac{12.8 x}{1 0 ^{5}} + \frac{2}{5 ^{6}} = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - \frac{12.8}{1 0 ^{5}} ) \pm ( - \frac{12.8}{1 0 ^{5}} ) ^{2} - 4 \cdot \frac{25.1}{1000000} \cdot \frac{2}{5 ^{6}}}{2 \cdot \frac{25.1}{1000000}}

(- \frac{12.8}{1 0 ^{5}})^{2} - 4 \cdot \frac{25.1}{1000000} \cdot \frac{2}{5 ^{6}} = \frac{163.84}{1 0 ^{10}} - \frac{200.8}{15625000000}

x_{1, 2} = \frac{- ( - \frac{12.8}{1 0 ^{5}} ) \pm \frac{163.84}{1 0 ^{10}} - \frac{200.8}{15625000000}}{2 \cdot \frac{25.1}{1000000}}

Separate the solutions

x_{1} = \frac{- ( - \frac{12.8}{1 0 ^{5}} ) + \frac{163.84}{1 0 ^{10}} - \frac{200.8}{15625000000}}{2 \cdot \frac{25.1}{1000000}}, x_{2} = \frac{- ( - \frac{12.8}{1 0 ^{5}} ) - \frac{163.84}{1 0 ^{10}} - \frac{200.8}{15625000000}}{2 \cdot \frac{25.1}{1000000}}

x = \frac{- ( - \frac{12.8}{1 0 ^{5}} ) + \frac{163.84}{1 0 ^{10}} - \frac{200.8}{15625000000}}{2 \frac{25.1}{1000000}} : \frac{50 ( 100000 \frac{163.84}{1 0 ^{10}} - \frac{200.8}{15625000000} + 12.8 )}{251}

x = \frac{- ( - \frac{12.8}{1 0 ^{5}} ) - \frac{163.84}{1 0 ^{10}} - \frac{200.8}{15625000000}}{2 \frac{25.1}{1000000}} : \frac{50 ( - 100000 \frac{163.84}{1 0 ^{10}} - \frac{200.8}{15625000000} + 12.8 )}{251}

The solutions to the quadratic equation are:

x = \frac{50 ( 100000 \frac{163.84}{1 0 ^{10}} - \frac{200.8}{15625000000} + 12.8 )}{251}, x = \frac{50 ( - 100000 \frac{163.84}{1 0 ^{10}} - \frac{200.8}{15625000000} + 12.8 )}{251}

3 x - 2 = 10

\frac{x ^{2} + 1}{x - 1} \leq 0

49 - x^{2}

5 x + 3 \leq 6 x - 8

\frac{2 x + 1}{3 x - 1} \geq \frac{2 x + 5}{3 x + 2}

What are the solutions to the equation (3.2*10^{-5})(2-x)^2=(6.9*10^{-6})x^2 ?
The solutions to the equation (3.2*10^{-5})(2-x)^2=(6.9*10^{-6})x^2 are
Find the zeros of (3.2*10^{-5})(2-x)^2=(6.9*10^{-6})x^2
The zeros of (3.2*10^{-5})(2-x)^2=(6.9*10^{-6})x^2 are