What are the solutions to the equation 2(3x+10)^2-31=11 ?

The solutions to the equation 2(3x+10)^2-31=11 are x=(sqrt(21)-10)/3 ,x=(-sqrt(21)-10)/3

Find the zeros of 2(3x+10)^2-31=11

The zeros of 2(3x+10)^2-31=11 are x=(sqrt(21)-10)/3 ,x=(-sqrt(21)-10)/3

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2 (3 x + 10)^{2} - 31 = 11

x = \frac{21 - 10}{3}, x = \frac{- 21 - 10}{3}

Decimal Notation

x = - 1.80580 \dots, x = - 4.86085 \dots

Solution steps

2 (3 x + 10)^{2} - 31 = 11

Move

31

to the right side

2 (3 x + 10)^{2} = 42

Divide both sides by

2

(3 x + 10)^{2} = 21

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x + 10 = 21 : x = \frac{21 - 10}{3}

Solve

3 x + 10 = - 21 : x = \frac{- 21 - 10}{3}

The solutions to the quadratic equation are:

x = \frac{21 - 10}{3}, x = \frac{- 21 - 10}{3}

y^{2} + y - 4 = 0

36 p^{2} + 12 p + 1 = 0

9 (5 - 5 x)^{2} + 10 = 11

x^{2} + 76 = 18 x

x^{2} - 14 x + 49 = 9

What are the solutions to the equation 2(3x+10)^2-31=11 ?
The solutions to the equation 2(3x+10)^2-31=11 are x=(sqrt(21)-10)/3 ,x=(-sqrt(21)-10)/3
Find the zeros of 2(3x+10)^2-31=11
The zeros of 2(3x+10)^2-31=11 are x=(sqrt(21)-10)/3 ,x=(-sqrt(21)-10)/3