What are the solutions to the equation solvefor a,n=4a^2-m ?

The solutions to the equation solvefor a,n=4a^2-m are a=(sqrt(n+m))/2 ,a=-(sqrt(n+m))/2

Find the zeros of solvefor a,n=4a^2-m

The zeros of solvefor a,n=4a^2-m are a=(sqrt(n+m))/2 ,a=-(sqrt(n+m))/2

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solve for

a, n = 4 a^{2} - m

a = \frac{n + m}{2}, a = - \frac{n + m}{2}

Solution steps

n = 4 a^{2} - m

Switch sides

4 a^{2} - m = n

Move

m

to the right side

4 a^{2} = n + m

Divide both sides by

4

a^{2} = \frac{n + m}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

a = \frac{n + m}{4}, a = - \frac{n + m}{4}

Simplify

\frac{n + m}{4} : \frac{n + m}{2}

Simplify

- \frac{n + m}{4} : - \frac{n + m}{2}

a = \frac{n + m}{2}, a = - \frac{n + m}{2}

a^{2} + 10 a + 25 = 0

- 3 x^{2} + 9 x = 0

y^{2} - y

4 x^{2} - 8 x + 12

10 x^{2} - 20 = 0

What are the solutions to the equation solvefor a,n=4a^2-m ?
The solutions to the equation solvefor a,n=4a^2-m are a=(sqrt(n+m))/2 ,a=-(sqrt(n+m))/2
Find the zeros of solvefor a,n=4a^2-m
The zeros of solvefor a,n=4a^2-m are a=(sqrt(n+m))/2 ,a=-(sqrt(n+m))/2