What are the solutions to the equation x(2x+3)=14 ?

The solutions to the equation x(2x+3)=14 are x=2,x=-7/2

Find the zeros of x(2x+3)=14

The zeros of x(2x+3)=14 are x=2,x=-7/2

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x (2 x + 3) = 14

x = 2, x = - \frac{7}{2}

Decimal Notation

x = 2, x = - 3.5

Solution steps

x (2 x + 3) = 14

Expand

x (2 x + 3) : 2 x^{2} + 3 x

2 x^{2} + 3 x = 14

Move

14

to the left side

2 x^{2} + 3 x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 2 ( - 14 )}{2 \cdot 2}

3^{2} - 4 \cdot 2 (- 14) = 11

x_{1, 2} = \frac{- 3 \pm 11}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 3 + 11}{2 \cdot 2}, x_{2} = \frac{- 3 - 11}{2 \cdot 2}

x = \frac{- 3 + 11}{2 \cdot 2} : 2

x = \frac{- 3 - 11}{2 \cdot 2} : - \frac{7}{2}

The solutions to the quadratic equation are:

x = 2, x = - \frac{7}{2}

0 = (x + 1)^{2}

x^{2} + 12 x = - 35

(x - 8) (x - 3) = 0

- (4 x - 5)^{2} + 3 = - 3

3 x^{2} + 6 x = - 2

What are the solutions to the equation x(2x+3)=14 ?
The solutions to the equation x(2x+3)=14 are x=2,x=-7/2
Find the zeros of x(2x+3)=14
The zeros of x(2x+3)=14 are x=2,x=-7/2