What are the solutions to the equation 4x^2+21x+5=0 ?

The solutions to the equation 4x^2+21x+5=0 are x=-1/4 ,x=-5

Find the zeros of 4x^2+21x+5=0

The zeros of 4x^2+21x+5=0 are x=-1/4 ,x=-5

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4 x^{2} + 21 x + 5 = 0

x = - \frac{1}{4}, x = - 5

Solution steps

4 x^{2} + 21 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 21 \pm 2 1 ^{2} - 4 \cdot 4 \cdot 5}{2 \cdot 4}

2 1^{2} - 4 \cdot 4 \cdot 5 = 19

x_{1, 2} = \frac{- 21 \pm 19}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 21 + 19}{2 \cdot 4}, x_{2} = \frac{- 21 - 19}{2 \cdot 4}

x = \frac{- 21 + 19}{2 \cdot 4} : - \frac{1}{4}

x = \frac{- 21 - 19}{2 \cdot 4} : - 5

The solutions to the quadratic equation are:

x = - \frac{1}{4}, x = - 5

\frac{1}{x + 3} > \frac{1}{4}

x^{2} - x + \frac{1}{4} = 0

∣ x ∣ \geq 7

- 3 (m - 2) + 9 (m + 5) = 8 m + 31

14 = \frac{1}{2} (9 x - 8)

What are the solutions to the equation 4x^2+21x+5=0 ?
The solutions to the equation 4x^2+21x+5=0 are x=-1/4 ,x=-5
Find the zeros of 4x^2+21x+5=0
The zeros of 4x^2+21x+5=0 are x=-1/4 ,x=-5