What are the solutions to the equation -x^2+16x-64=0 ?

The solutions to the equation -x^2+16x-64=0 are x=8

Find the zeros of -x^2+16x-64=0

The zeros of -x^2+16x-64=0 are x=8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- x^{2} + 16 x - 64 = 0

x = 8

Solution steps

- x^{2} + 16 x - 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 ( - 1 ) ( - 64 )}{2 ( - 1 )}

1 6^{2} - 4 (- 1) (- 64) = 0

x_{1, 2} = \frac{- 16 \pm 0}{2 ( - 1 )}

x = \frac{- 16}{2 ( - 1 )}

\frac{- 16}{2 ( - 1 )} = 8

x = 8

The solution to the quadratic equation is:

x = 8

x^{2} + 6 = 10 x

6 m^{2} = 7 m + 20

- x^{2} + \frac{1}{144} = 0

x, 3 x^{2} + 3 y^{2} + 3 z^{2} = 27

ab x^{2} + ab = x (a^{2} + b^{2})

What are the solutions to the equation -x^2+16x-64=0 ?
The solutions to the equation -x^2+16x-64=0 are x=8
Find the zeros of -x^2+16x-64=0
The zeros of -x^2+16x-64=0 are x=8