What are the solutions to the equation 5=-0.01q^2-0.4q+10 ?

The solutions to the equation 5=-0.01q^2-0.4q+10 are q=-50,q=10

Find the zeros of 5=-0.01q^2-0.4q+10

The zeros of 5=-0.01q^2-0.4q+10 are q=-50,q=10

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5 = - 0.01 q^{2} - 0.4 q + 10

q = - 50, q = 10

Solution steps

5 = - 0.01 q^{2} - 0.4 q + 10

Multiply both sides by

100

500 = - q^{2} - 40 q + 1000

Switch sides

- q^{2} - 40 q + 1000 = 500

Move

500

to the left side

- q^{2} - 40 q + 500 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- ( - 40 ) \pm ( - 40 ) ^{2} - 4 ( - 1 ) \cdot 500}{2 ( - 1 )}

(- 40)^{2} - 4 (- 1) \cdot 500 = 60

q_{1, 2} = \frac{- ( - 40 ) \pm 60}{2 ( - 1 )}

Separate the solutions

q_{1} = \frac{- ( - 40 ) + 60}{2 ( - 1 )}, q_{2} = \frac{- ( - 40 ) - 60}{2 ( - 1 )}

q = \frac{- ( - 40 ) + 60}{2 ( - 1 )} : - 50

q = \frac{- ( - 40 ) - 60}{2 ( - 1 )} : 10

The solutions to the quadratic equation are:

q = - 50, q = 10

8 x^{2} - 1 = 0

x^{2} + 49 = 85

(2 x - 3)^{2} = (x - 5)^{2} + (2 x + 3) (2 x - 7)

x^{2} = 5^{2} + 5^{2}

3 x^{2} + 54 = 0

What are the solutions to the equation 5=-0.01q^2-0.4q+10 ?
The solutions to the equation 5=-0.01q^2-0.4q+10 are q=-50,q=10
Find the zeros of 5=-0.01q^2-0.4q+10
The zeros of 5=-0.01q^2-0.4q+10 are q=-50,q=10