What are the solutions to the equation 12x^2-148x+336=0 ?

The solutions to the equation 12x^2-148x+336=0 are x= 28/3 ,x=3

Find the zeros of 12x^2-148x+336=0

The zeros of 12x^2-148x+336=0 are x= 28/3 ,x=3

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12 x^{2} - 148 x + 336 = 0

x = \frac{28}{3}, x = 3

Decimal Notation

x = 9.33333 \dots, x = 3

Solution steps

12 x^{2} - 148 x + 336 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 148 ) \pm ( - 148 ) ^{2} - 4 \cdot 12 \cdot 336}{2 \cdot 12}

(- 148)^{2} - 4 \cdot 12 \cdot 336 = 76

x_{1, 2} = \frac{- ( - 148 ) \pm 76}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 148 ) + 76}{2 \cdot 12}, x_{2} = \frac{- ( - 148 ) - 76}{2 \cdot 12}

x = \frac{- ( - 148 ) + 76}{2 \cdot 12} : \frac{28}{3}

x = \frac{- ( - 148 ) - 76}{2 \cdot 12} : 3

The solutions to the quadratic equation are:

x = \frac{28}{3}, x = 3

x^{2} + 12 + 20 x = 0

9 x^{2} - 6 x + 38 = 0

s^{2} - 4 s + 13

2 x^{2} - 6 x = 6 x^{2} - 8 x

x, 2 z = x^{2} + y^{2}

What are the solutions to the equation 12x^2-148x+336=0 ?
The solutions to the equation 12x^2-148x+336=0 are x= 28/3 ,x=3
Find the zeros of 12x^2-148x+336=0
The zeros of 12x^2-148x+336=0 are x= 28/3 ,x=3