What are the solutions to the equation x^2+x-0.5=0 ?

The solutions to the equation x^2+x-0.5=0 are x=(-1+sqrt(3))/2 ,x=-(1+sqrt(3))/2

Find the zeros of x^2+x-0.5=0

The zeros of x^2+x-0.5=0 are x=(-1+sqrt(3))/2 ,x=-(1+sqrt(3))/2

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x^{2} + x - 0.5 = 0

x = \frac{- 1 + 3}{2}, x = - \frac{1 + 3}{2}

Decimal Notation

x = 0.36602 \dots, x = - 1.36602 \dots

Solution steps

x^{2} + x - 0.5 = 0

Multiply both sides by

10

10 x^{2} + 10 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 10 ( - 5 )}{2 \cdot 10}

1 0^{2} - 4 \cdot 10 (- 5) = 103

x_{1, 2} = \frac{- 10 \pm 10 3}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- 10 + 10 3}{2 \cdot 10}, x_{2} = \frac{- 10 - 10 3}{2 \cdot 10}

x = \frac{- 10 + 10 3}{2 \cdot 10} : \frac{- 1 + 3}{2}

x = \frac{- 10 - 10 3}{2 \cdot 10} : - \frac{1 + 3}{2}

The solutions to the quadratic equation are:

x = \frac{- 1 + 3}{2}, x = - \frac{1 + 3}{2}

x^{2} - 4 x - 21 = 0

- 2 x^{2} + 9 x + 29 = - 6

x, 2 x^{2} - 3 x y + 3 y^{2} = 50

11 r + 15 = - 2 r^{2}

12 x - 2 x^{2} = 0

What are the solutions to the equation x^2+x-0.5=0 ?
The solutions to the equation x^2+x-0.5=0 are x=(-1+sqrt(3))/2 ,x=-(1+sqrt(3))/2
Find the zeros of x^2+x-0.5=0
The zeros of x^2+x-0.5=0 are x=(-1+sqrt(3))/2 ,x=-(1+sqrt(3))/2