What are the solutions to the equation 2x^2-7x-11=0 ?

The solutions to the equation 2x^2-7x-11=0 are x=(7+sqrt(137))/4 ,x=(7-sqrt(137))/4

Find the zeros of 2x^2-7x-11=0

The zeros of 2x^2-7x-11=0 are x=(7+sqrt(137))/4 ,x=(7-sqrt(137))/4

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2 x^{2} - 7 x - 11 = 0

x = \frac{7 + 137}{4}, x = \frac{7 - 137}{4}

Decimal Notation

x = 4.67617 \dots, x = - 1.17617 \dots

Solution steps

2 x^{2} - 7 x - 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 2 ( - 11 )}{2 \cdot 2}

(- 7)^{2} - 4 \cdot 2 (- 11) = 137

x_{1, 2} = \frac{- ( - 7 ) \pm 137}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 137}{2 \cdot 2}, x_{2} = \frac{- ( - 7 ) - 137}{2 \cdot 2}

x = \frac{- ( - 7 ) + 137}{2 \cdot 2} : \frac{7 + 137}{4}

x = \frac{- ( - 7 ) - 137}{2 \cdot 2} : \frac{7 - 137}{4}

The solutions to the quadratic equation are:

x = \frac{7 + 137}{4}, x = \frac{7 - 137}{4}

5 x^{2} + 3 = x

5 x^{2} + 2 = 6

x^{2} - 3 x + 5

x^{2} - 3 x + 1

x^{2} - 53 = - 98

What are the solutions to the equation 2x^2-7x-11=0 ?
The solutions to the equation 2x^2-7x-11=0 are x=(7+sqrt(137))/4 ,x=(7-sqrt(137))/4
Find the zeros of 2x^2-7x-11=0
The zeros of 2x^2-7x-11=0 are x=(7+sqrt(137))/4 ,x=(7-sqrt(137))/4