What are the solutions to the equation 0=3x^2+2x-1 ?

The solutions to the equation 0=3x^2+2x-1 are x= 1/3 ,x=-1

Find the zeros of 0=3x^2+2x-1

The zeros of 0=3x^2+2x-1 are x= 1/3 ,x=-1

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0 = 3 x^{2} + 2 x - 1

x = \frac{1}{3}, x = - 1

Decimal Notation

x = 0.33333 \dots, x = - 1

Solution steps

0 = 3 x^{2} + 2 x - 1

Switch sides

3 x^{2} + 2 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 3 ( - 1 )}{2 \cdot 3}

2^{2} - 4 \cdot 3 (- 1) = 4

x_{1, 2} = \frac{- 2 \pm 4}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 2 + 4}{2 \cdot 3}, x_{2} = \frac{- 2 - 4}{2 \cdot 3}

x = \frac{- 2 + 4}{2 \cdot 3} : \frac{1}{3}

x = \frac{- 2 - 4}{2 \cdot 3} : - 1

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = - 1

y = x^{2}, x

12 x^{2} = 25 x

4 (x + 1)^{2} + 12 = 0

7 v^{2} - 14 v + 4 = 3

9 x^{2} + 30 x + 28 = 0

What are the solutions to the equation 0=3x^2+2x-1 ?
The solutions to the equation 0=3x^2+2x-1 are x= 1/3 ,x=-1
Find the zeros of 0=3x^2+2x-1
The zeros of 0=3x^2+2x-1 are x= 1/3 ,x=-1