What are the solutions to the equation (-3-x)*(3-x)=0 ?

The solutions to the equation (-3-x)*(3-x)=0 are x=-3,x=3

Find the zeros of (-3-x)*(3-x)=0

The zeros of (-3-x)*(3-x)=0 are x=-3,x=3

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(- 3 - x) \cdot (3 - x) = 0

x = - 3, x = 3

Solution steps

(- 3 - x) (3 - x) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

- 3 - x = 0 or 3 - x = 0

Solve

- 3 - x = 0 : x = - 3

Solve

3 - x = 0 : x = 3

The solutions to the quadratic equation are:

x = - 3, x = 3

21 x^{2} - 60 x + 40 = 0

3 + 5 z + z^{2} = 0

6 x^{2} + x - 15 = 8

3 x^{2} + 2 x + \frac{1}{4} = 0

(x - 4)^{2} = - 81

What are the solutions to the equation (-3-x)*(3-x)=0 ?
The solutions to the equation (-3-x)*(3-x)=0 are x=-3,x=3
Find the zeros of (-3-x)*(3-x)=0
The zeros of (-3-x)*(3-x)=0 are x=-3,x=3