What are the solutions to the equation 5m^2-7m-11=0 ?

The solutions to the equation 5m^2-7m-11=0 are m=(7+sqrt(269))/(10),m=(7-sqrt(269))/(10)

Find the zeros of 5m^2-7m-11=0

The zeros of 5m^2-7m-11=0 are m=(7+sqrt(269))/(10),m=(7-sqrt(269))/(10)

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5 m^{2} - 7 m - 11 = 0

m = \frac{7 + 269}{10}, m = \frac{7 - 269}{10}

Decimal Notation

m = 2.34012 \dots, m = - 0.94012 \dots

Solution steps

5 m^{2} - 7 m - 11 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 5 ( - 11 )}{2 \cdot 5}

(- 7)^{2} - 4 \cdot 5 (- 11) = 269

m_{1, 2} = \frac{- ( - 7 ) \pm 269}{2 \cdot 5}

Separate the solutions

m_{1} = \frac{- ( - 7 ) + 269}{2 \cdot 5}, m_{2} = \frac{- ( - 7 ) - 269}{2 \cdot 5}

m = \frac{- ( - 7 ) + 269}{2 \cdot 5} : \frac{7 + 269}{10}

m = \frac{- ( - 7 ) - 269}{2 \cdot 5} : \frac{7 - 269}{10}

The solutions to the quadratic equation are:

m = \frac{7 + 269}{10}, m = \frac{7 - 269}{10}

m^{2} + 4 m - 12 = 0

x - 1 = x^{2} - 14 x + 49

3 x^{2} + 18 x

x^{2} + 3 x + 2

- 3 x^{2} = 48

What are the solutions to the equation 5m^2-7m-11=0 ?
The solutions to the equation 5m^2-7m-11=0 are m=(7+sqrt(269))/(10),m=(7-sqrt(269))/(10)
Find the zeros of 5m^2-7m-11=0
The zeros of 5m^2-7m-11=0 are m=(7+sqrt(269))/(10),m=(7-sqrt(269))/(10)