What are the solutions to the equation x^2+400x+200000=0 ?

The solutions to the equation x^2+400x+200000=0 are x=-200+400i,x=-200-400i

Find the zeros of x^2+400x+200000=0

The zeros of x^2+400x+200000=0 are x=-200+400i,x=-200-400i

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x^{2} + 400 x + 200000 = 0

x = - 200 + 400 i, x = - 200 - 400 i

Solution steps

x^{2} + 400 x + 200000 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 400 \pm 40 0 ^{2} - 4 \cdot 1 \cdot 200000}{2 \cdot 1}

Simplify

40 0^{2} - 4 \cdot 1 \cdot 200000 : 800 i

x_{1, 2} = \frac{- 400 \pm 800 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 400 + 800 i}{2 \cdot 1}, x_{2} = \frac{- 400 - 800 i}{2 \cdot 1}

x = \frac{- 400 + 800 i}{2 \cdot 1} : - 200 + 400 i

x = \frac{- 400 - 800 i}{2 \cdot 1} : - 200 - 400 i

The solutions to the quadratic equation are:

x = - 200 + 400 i, x = - 200 - 400 i

h^{2} + 6 h = 16

- 2 x^{2} - 24 x = 0

(x - 5)^{2} - 100 = 0

(1 + x)^{2} + (2 + x)^{2} = (3 - x)^{2}

v, a = \frac{v ^{2}}{r}

What are the solutions to the equation x^2+400x+200000=0 ?
The solutions to the equation x^2+400x+200000=0 are x=-200+400i,x=-200-400i
Find the zeros of x^2+400x+200000=0
The zeros of x^2+400x+200000=0 are x=-200+400i,x=-200-400i