What are the solutions to the equation 4m^2+12m+9=0 ?

The solutions to the equation 4m^2+12m+9=0 are m=-3/2

Find the zeros of 4m^2+12m+9=0

The zeros of 4m^2+12m+9=0 are m=-3/2

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4 m^{2} + 12 m + 9 = 0

m = - \frac{3}{2}

Decimal Notation

m = - 1.5

Solution steps

4 m^{2} + 12 m + 9 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 4 \cdot 9}{2 \cdot 4}

1 2^{2} - 4 \cdot 4 \cdot 9 = 0

m_{1, 2} = \frac{- 12 \pm 0}{2 \cdot 4}

m = \frac{- 12}{2 \cdot 4}

\frac{- 12}{2 \cdot 4} = - \frac{3}{2}

m = - \frac{3}{2}

The solution to the quadratic equation is:

m = - \frac{3}{2}

5 x^{2} + 20 x + 20 = 0

x^{2} + 2 x - 15

- 0.0241 x^{2} + x + 5.5 = 0

(x + 2)^{2} = 3 (x + 2)

x^{2} + x - \frac{1}{2} = 0

What are the solutions to the equation 4m^2+12m+9=0 ?
The solutions to the equation 4m^2+12m+9=0 are m=-3/2
Find the zeros of 4m^2+12m+9=0
The zeros of 4m^2+12m+9=0 are m=-3/2