What are the solutions to the equation 2r^2-8r=-64 ?

The solutions to the equation 2r^2-8r=-64 are r=2+2sqrt(7)i,r=2-2sqrt(7)i

Find the zeros of 2r^2-8r=-64

The zeros of 2r^2-8r=-64 are r=2+2sqrt(7)i,r=2-2sqrt(7)i

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2 r^{2} - 8 r = - 64

r = 2 + 27 i, r = 2 - 27 i

Solution steps

2 r^{2} - 8 r = - 64

Move

64

to the left side

2 r^{2} - 8 r + 64 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 2 \cdot 64}{2 \cdot 2}

Simplify

(- 8)^{2} - 4 \cdot 2 \cdot 64 : 87 i

r_{1, 2} = \frac{- ( - 8 ) \pm 8 7 i}{2 \cdot 2}

Separate the solutions

r_{1} = \frac{- ( - 8 ) + 8 7 i}{2 \cdot 2}, r_{2} = \frac{- ( - 8 ) - 8 7 i}{2 \cdot 2}

r = \frac{- ( - 8 ) + 8 7 i}{2 \cdot 2} : 2 + 27 i

r = \frac{- ( - 8 ) - 8 7 i}{2 \cdot 2} : 2 - 27 i

The solutions to the quadratic equation are:

r = 2 + 27 i, r = 2 - 27 i

x^{2} + 5 x + 4

x^{2} + 5 x + 7

x^{2} = - 40

(x - 5) (40 - x) = 4 (x - 5)

x^{2} + 6 x + 14 = (x - h) 2 + k

What are the solutions to the equation 2r^2-8r=-64 ?
The solutions to the equation 2r^2-8r=-64 are r=2+2sqrt(7)i,r=2-2sqrt(7)i
Find the zeros of 2r^2-8r=-64
The zeros of 2r^2-8r=-64 are r=2+2sqrt(7)i,r=2-2sqrt(7)i