What are the solutions to the equation -3x^2+8x-2=-6 ?

The solutions to the equation -3x^2+8x-2=-6 are x=-(2(sqrt(7)-2))/3 ,x=(2(2+sqrt(7)))/3

Find the zeros of -3x^2+8x-2=-6

The zeros of -3x^2+8x-2=-6 are x=-(2(sqrt(7)-2))/3 ,x=(2(2+sqrt(7)))/3

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- 3 x^{2} + 8 x - 2 = - 6

x = - \frac{2 ( 7 - 2 )}{3}, x = \frac{2 ( 2 + 7 )}{3}

Decimal Notation

x = - 0.43050 \dots, x = 3.09716 \dots

Solution steps

- 3 x^{2} + 8 x - 2 = - 6

Move

6

to the left side

- 3 x^{2} + 8 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 3 ) \cdot 4}{2 ( - 3 )}

8^{2} - 4 (- 3) \cdot 4 = 47

x_{1, 2} = \frac{- 8 \pm 4 7}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 8 + 4 7}{2 ( - 3 )}, x_{2} = \frac{- 8 - 4 7}{2 ( - 3 )}

x = \frac{- 8 + 4 7}{2 ( - 3 )} : - \frac{2 ( 7 - 2 )}{3}

x = \frac{- 8 - 4 7}{2 ( - 3 )} : \frac{2 ( 2 + 7 )}{3}

The solutions to the quadratic equation are:

x = - \frac{2 ( 7 - 2 )}{3}, x = \frac{2 ( 2 + 7 )}{3}

y^{2} + 4 y - 7 = 0

(4 x + 1) (8 x - 1) = 16 x + 3

27 x^{2} = 12

5 y^{2} + 4 y - 2 = 0

- 2 x^{2} + 6 x + 7 = 2 x - 3

What are the solutions to the equation -3x^2+8x-2=-6 ?
The solutions to the equation -3x^2+8x-2=-6 are x=-(2(sqrt(7)-2))/3 ,x=(2(2+sqrt(7)))/3
Find the zeros of -3x^2+8x-2=-6
The zeros of -3x^2+8x-2=-6 are x=-(2(sqrt(7)-2))/3 ,x=(2(2+sqrt(7)))/3