What are the solutions to the equation -2x^2+6x+7=2x-3 ?

The solutions to the equation -2x^2+6x+7=2x-3 are x=1-sqrt(6),x=1+sqrt(6)

Find the zeros of -2x^2+6x+7=2x-3

The zeros of -2x^2+6x+7=2x-3 are x=1-sqrt(6),x=1+sqrt(6)

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- 2 x^{2} + 6 x + 7 = 2 x - 3

x = 1 - 6, x = 1 + 6

Decimal Notation

x = - 1.44948 \dots, x = 3.44948 \dots

Solution steps

- 2 x^{2} + 6 x + 7 = 2 x - 3

Move

3

to the left side

- 2 x^{2} + 6 x + 10 = 2 x

Move

2 x

to the left side

- 2 x^{2} + 4 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 2 ) \cdot 10}{2 ( - 2 )}

4^{2} - 4 (- 2) \cdot 10 = 46

x_{1, 2} = \frac{- 4 \pm 4 6}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 4 + 4 6}{2 ( - 2 )}, x_{2} = \frac{- 4 - 4 6}{2 ( - 2 )}

x = \frac{- 4 + 4 6}{2 ( - 2 )} : 1 - 6

x = \frac{- 4 - 4 6}{2 ( - 2 )} : 1 + 6

The solutions to the quadratic equation are:

x = 1 - 6, x = 1 + 6

x^{2} + 2 x + 20 = - 9

15 p^{2} + 80 p + 80 = 0

7 x^{2} - 5 = 0

x^{2} - 2 x + 1 = 80

3 a^{2} - a + 2 = 7 a

What are the solutions to the equation -2x^2+6x+7=2x-3 ?
The solutions to the equation -2x^2+6x+7=2x-3 are x=1-sqrt(6),x=1+sqrt(6)
Find the zeros of -2x^2+6x+7=2x-3
The zeros of -2x^2+6x+7=2x-3 are x=1-sqrt(6),x=1+sqrt(6)