What are the solutions to the equation x^2+x+5=7+2x ?

The solutions to the equation x^2+x+5=7+2x are x=2,x=-1

Find the zeros of x^2+x+5=7+2x

The zeros of x^2+x+5=7+2x are x=2,x=-1

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x^{2} + x + 5 = 7 + 2 x

x = 2, x = - 1

Solution steps

x^{2} + x + 5 = 7 + 2 x

Move

2 x

to the left side

x^{2} - x + 5 = 7

Move

7

to the left side

x^{2} - x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 2) = 3

x_{1, 2} = \frac{- ( - 1 ) \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 3}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 3}{2 \cdot 1}

x = \frac{- ( - 1 ) + 3}{2 \cdot 1} : 2

x = \frac{- ( - 1 ) - 3}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 2, x = - 1

v, \frac{1}{2} m v^{2} = \frac{1}{2} k x^{2}

4^{2} = 3^{2} + x^{2}

5 p^{2} = 4 + p

- 3 m^{2} + 6 m + 24 = 0

x^{2} + 7 x + 4

What are the solutions to the equation x^2+x+5=7+2x ?
The solutions to the equation x^2+x+5=7+2x are x=2,x=-1
Find the zeros of x^2+x+5=7+2x
The zeros of x^2+x+5=7+2x are x=2,x=-1