What are the solutions to the equation solvefor x,z=1+x^2+y^2 ?

The solutions to the equation solvefor x,z=1+x^2+y^2 are x=sqrt(z-y^2-1),x=-sqrt(z-y^2-1)

Find the zeros of solvefor x,z=1+x^2+y^2

The zeros of solvefor x,z=1+x^2+y^2 are x=sqrt(z-y^2-1),x=-sqrt(z-y^2-1)

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solve for

x, z = 1 + x^{2} + y^{2}

x = z - y^{2} - 1, x = - z - y^{2} - 1

Solution steps

z = 1 + x^{2} + y^{2}

Switch sides

1 + x^{2} + y^{2} = z

Move

y^{2}

to the right side

1 + x^{2} = z - y^{2}

Move

1

to the right side

x^{2} = z - y^{2} - 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = z - y^{2} - 1, x = - z - y^{2} - 1

5 x^{2} + 2 = 4 x

x^{2} + \frac{2}{5} x + 3

6 x^{2} + 7 x + 3 = 0

x^{2} - 7 x - 18 = 0

(v + 3) (v + 11) - 57 = - v (v + 8)

What are the solutions to the equation solvefor x,z=1+x^2+y^2 ?
The solutions to the equation solvefor x,z=1+x^2+y^2 are x=sqrt(z-y^2-1),x=-sqrt(z-y^2-1)
Find the zeros of solvefor x,z=1+x^2+y^2
The zeros of solvefor x,z=1+x^2+y^2 are x=sqrt(z-y^2-1),x=-sqrt(z-y^2-1)