What are the solutions to the equation (2x+5)(x-1)=-6 ?

The solutions to the equation (2x+5)(x-1)=-6 are x=-1/2 ,x=-1

Find the zeros of (2x+5)(x-1)=-6

The zeros of (2x+5)(x-1)=-6 are x=-1/2 ,x=-1

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(2 x + 5) (x - 1) = - 6

x = - \frac{1}{2}, x = - 1

Decimal Notation

x = - 0.5, x = - 1

Solution steps

(2 x + 5) (x - 1) = - 6

Expand

(2 x + 5) (x - 1) : 2 x^{2} + 3 x - 5

2 x^{2} + 3 x - 5 = - 6

Move

6

to the left side

2 x^{2} + 3 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 2 \cdot 1}{2 \cdot 2}

3^{2} - 4 \cdot 2 \cdot 1 = 1

x_{1, 2} = \frac{- 3 \pm 1}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 3 + 1}{2 \cdot 2}, x_{2} = \frac{- 3 - 1}{2 \cdot 2}

x = \frac{- 3 + 1}{2 \cdot 2} : - \frac{1}{2}

x = \frac{- 3 - 1}{2 \cdot 2} : - 1

The solutions to the quadratic equation are:

x = - \frac{1}{2}, x = - 1

u^{2} = - 25

12 x^{2} - 30 x + 12 = 0

6 x^{2} + 4 x + 11 = 2

4 x^{2} - 20 x = - 25

3 x^{2} - 20 x + 20 = 0

What are the solutions to the equation (2x+5)(x-1)=-6 ?
The solutions to the equation (2x+5)(x-1)=-6 are x=-1/2 ,x=-1
Find the zeros of (2x+5)(x-1)=-6
The zeros of (2x+5)(x-1)=-6 are x=-1/2 ,x=-1